6w^2-17w-28=0

Solution for 6w^2-17w-28=0 equation:

6w^2-17w-28=0

a = 6; b = -17; c = -28;
Δ = b2-4ac
Δ = -172-4·6·(-28)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-31}{2*6}=\frac{-14}{12}
=-1+1/6
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+31}{2*6}=\frac{48}{12}
=4
$